Metamath Proof Explorer


Theorem ifnot

Description: Negating the first argument swaps the last two arguments of a conditional operator. (Contributed by NM, 21-Jun-2007)

Ref Expression
Assertion ifnot ⊢ if ¬ φ A B = if φ B A

Proof

Step Hyp Ref Expression
1 notnot ⊢ φ → ¬ ¬ φ
2 1 iffalsed ⊢ φ → if ¬ φ A B = B
3 iftrue ⊢ φ → if φ B A = B
4 2 3 eqtr4d ⊢ φ → if ¬ φ A B = if φ B A
5 iftrue ⊢ ¬ φ → if ¬ φ A B = A
6 iffalse ⊢ ¬ φ → if φ B A = A
7 5 6 eqtr4d ⊢ ¬ φ → if ¬ φ A B = if φ B A
8 4 7 pm2.61i ⊢ if ¬ φ A B = if φ B A