Metamath Proof Explorer


Theorem ifnot

Description: Negating the first argument swaps the last two arguments of a conditional operator. (Contributed by NM, 21-Jun-2007)

Ref Expression
Assertion ifnot if ( ¬ 𝜑 , 𝐴 , 𝐵 ) = if ( 𝜑 , 𝐵 , 𝐴 )

Proof

Step Hyp Ref Expression
1 notnot ⊢ ( 𝜑 → ¬ ¬ 𝜑 )
2 1 iffalsed ⊢ ( 𝜑 → if ( ¬ 𝜑 , 𝐴 , 𝐵 ) = 𝐵 )
3 iftrue ⊢ ( 𝜑 → if ( 𝜑 , 𝐵 , 𝐴 ) = 𝐵 )
4 2 3 eqtr4d ⊢ ( 𝜑 → if ( ¬ 𝜑 , 𝐴 , 𝐵 ) = if ( 𝜑 , 𝐵 , 𝐴 ) )
5 iftrue ⊢ ( ¬ 𝜑 → if ( ¬ 𝜑 , 𝐴 , 𝐵 ) = 𝐴 )
6 iffalse ⊢ ( ¬ 𝜑 → if ( 𝜑 , 𝐵 , 𝐴 ) = 𝐴 )
7 5 6 eqtr4d ⊢ ( ¬ 𝜑 → if ( ¬ 𝜑 , 𝐴 , 𝐵 ) = if ( 𝜑 , 𝐵 , 𝐴 ) )
8 4 7 pm2.61i ⊢ if ( ¬ 𝜑 , 𝐴 , 𝐵 ) = if ( 𝜑 , 𝐵 , 𝐴 )