Metamath Proof Explorer


Theorem ifov

Description: Move a conditional outside of an operation. (Contributed by AV, 11-Nov-2019)

Ref Expression
Assertion ifov AifφFGB=ifφAFBAGB

Proof

Step Hyp Ref Expression
1 oveq ifφFG=FAifφFGB=AFB
2 oveq ifφFG=GAifφFGB=AGB
3 1 2 ifsb AifφFGB=ifφAFBAGB