Metamath Proof Explorer


Theorem in13

Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012)

Ref Expression
Assertion in13 ABC=CBA

Proof

Step Hyp Ref Expression
1 in32 BCA=BAC
2 incom ABC=BCA
3 incom CBA=BAC
4 1 2 3 3eqtr4i ABC=CBA