Metamath Proof Explorer


Theorem ineqri

Description: Inference from membership to intersection. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypothesis ineqri.1 ⊢ x ∈ A ∧ x ∈ B ↔ x ∈ C
Assertion ineqri ⊢ A ∩ B = C

Proof

Step Hyp Ref Expression
1 ineqri.1 ⊢ x ∈ A ∧ x ∈ B ↔ x ∈ C
2 elin ⊢ x ∈ A ∩ B ↔ x ∈ A ∧ x ∈ B
3 2 1 bitri ⊢ x ∈ A ∩ B ↔ x ∈ C
4 3 eqriv ⊢ A ∩ B = C