Metamath Proof Explorer


Theorem intss

Description: Intersection of subclasses. (Contributed by NM, 14-Oct-1999) (Proof shortened by OpenAI, 25-Mar-2020)

Ref Expression
Assertion intss ⊢ A ⊆ B → ⋂ B ⊆ ⋂ A

Proof

Step Hyp Ref Expression
1 ssralv ⊢ A ⊆ B → ∀ x ∈ B y ∈ x → ∀ x ∈ A y ∈ x
2 1 ss2abdv ⊢ A ⊆ B → y | ∀ x ∈ B y ∈ x ⊆ y | ∀ x ∈ A y ∈ x
3 dfint2 ⊢ ⋂ B = y | ∀ x ∈ B y ∈ x
4 dfint2 ⊢ ⋂ A = y | ∀ x ∈ A y ∈ x
5 2 3 4 3sstr4g ⊢ A ⊆ B → ⋂ B ⊆ ⋂ A