Metamath Proof Explorer


Theorem iotabidv

Description: Formula-building deduction for iota. (Contributed by NM, 20-Aug-2011)

Ref Expression
Hypothesis iotabidv.1 ⊢ φ → ψ ↔ χ
Assertion iotabidv ⊢ φ → ι x | ψ = ι x | χ

Proof

Step Hyp Ref Expression
1 iotabidv.1 ⊢ φ → ψ ↔ χ
2 1 alrimiv ⊢ φ → ∀ x ψ ↔ χ
3 iotabi ⊢ ∀ x ψ ↔ χ → ι x | ψ = ι x | χ
4 2 3 syl ⊢ φ → ι x | ψ = ι x | χ