Metamath Proof Explorer


Theorem iotabidv

Description: Formula-building deduction for iota. (Contributed by NM, 20-Aug-2011)

Ref Expression
Hypothesis iotabidv.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
Assertion iotabidv ( 𝜑 → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑥 𝜒 ) )

Proof

Step Hyp Ref Expression
1 iotabidv.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 1 alrimiv ⊢ ( 𝜑 → ∀ 𝑥 ( 𝜓 ↔ 𝜒 ) )
3 iotabi ⊢ ( ∀ 𝑥 ( 𝜓 ↔ 𝜒 ) → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑥 𝜒 ) )
4 2 3 syl ⊢ ( 𝜑 → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑥 𝜒 ) )