Metamath Proof Explorer


Theorem iseqlgd

Description: Condition for a triangle to be equilateral. (Contributed by Thierry Arnoux, 5-Oct-2020)

Ref Expression
Hypotheses iseqlg.p ⊢ P = Base G
iseqlg.m ⊢ - ˙ = dist ⁡ G
iseqlg.i ⊢ I = Itv ⁡ G
iseqlg.l ⊢ L = Line 𝒢 ⁡ G
iseqlg.g ⊢ φ → G ∈ 𝒢 Tarski
iseqlg.a ⊢ φ → A ∈ P
iseqlg.b ⊢ φ → B ∈ P
iseqlg.c ⊢ φ → C ∈ P
iseqlgd.1 ⊢ φ → A - ˙ B = B - ˙ C
iseqlgd.2 ⊢ φ → B - ˙ C = C - ˙ A
iseqlgd.3 ⊢ φ → C - ˙ A = A - ˙ B
Assertion iseqlgd ⊢ φ → ⟨“ ABC ”⟩ ∈ Equilaterals 𝒢 ⁡ G

Proof

Step Hyp Ref Expression
1 iseqlg.p ⊢ P = Base G
2 iseqlg.m ⊢ - ˙ = dist ⁡ G
3 iseqlg.i ⊢ I = Itv ⁡ G
4 iseqlg.l ⊢ L = Line 𝒢 ⁡ G
5 iseqlg.g ⊢ φ → G ∈ 𝒢 Tarski
6 iseqlg.a ⊢ φ → A ∈ P
7 iseqlg.b ⊢ φ → B ∈ P
8 iseqlg.c ⊢ φ → C ∈ P
9 iseqlgd.1 ⊢ φ → A - ˙ B = B - ˙ C
10 iseqlgd.2 ⊢ φ → B - ˙ C = C - ˙ A
11 iseqlgd.3 ⊢ φ → C - ˙ A = A - ˙ B
12 eqid ⊢ ∼ 𝒢 ⁡ G = ∼ 𝒢 ⁡ G
13 1 2 12 5 6 7 8 7 8 6 9 10 11 trgcgr ⊢ φ → ⟨“ ABC ”⟩ ∼ 𝒢 ⁡ G ⟨“ BCA ”⟩
14 1 2 3 4 5 6 7 8 iseqlg ⊢ φ → ⟨“ ABC ”⟩ ∈ Equilaterals 𝒢 ⁡ G ↔ ⟨“ ABC ”⟩ ∼ 𝒢 ⁡ G ⟨“ BCA ”⟩
15 13 14 mpbird ⊢ φ → ⟨“ ABC ”⟩ ∈ Equilaterals 𝒢 ⁡ G