Metamath Proof Explorer


Theorem iseqlgd

Description: Condition for a triangle to be equilateral. (Contributed by Thierry Arnoux, 5-Oct-2020)

Ref Expression
Hypotheses iseqlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
iseqlg.m ⊢ − = ( dist ‘ 𝐺 )
iseqlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
iseqlg.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
iseqlg.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
iseqlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
iseqlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
iseqlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
iseqlgd.1 ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) = ( 𝐵 − 𝐶 ) )
iseqlgd.2 ⊢ ( 𝜑 → ( 𝐵 − 𝐶 ) = ( 𝐶 − 𝐴 ) )
iseqlgd.3 ⊢ ( 𝜑 → ( 𝐶 − 𝐴 ) = ( 𝐴 − 𝐵 ) )
Assertion iseqlgd ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ∈ ( eqltrG ‘ 𝐺 ) )

Proof

Step Hyp Ref Expression
1 iseqlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 iseqlg.m ⊢ − = ( dist ‘ 𝐺 )
3 iseqlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
4 iseqlg.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
5 iseqlg.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
6 iseqlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
7 iseqlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
8 iseqlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
9 iseqlgd.1 ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) = ( 𝐵 − 𝐶 ) )
10 iseqlgd.2 ⊢ ( 𝜑 → ( 𝐵 − 𝐶 ) = ( 𝐶 − 𝐴 ) )
11 iseqlgd.3 ⊢ ( 𝜑 → ( 𝐶 − 𝐴 ) = ( 𝐴 − 𝐵 ) )
12 eqid ⊢ ( cgrG ‘ 𝐺 ) = ( cgrG ‘ 𝐺 )
13 1 2 12 5 6 7 8 7 8 6 9 10 11 trgcgr ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrG ‘ 𝐺 ) ⟨“ 𝐵 𝐶 𝐴 ”⟩ )
14 1 2 3 4 5 6 7 8 iseqlg ⊢ ( 𝜑 → ( ⟨“ 𝐴 𝐵 𝐶 ”⟩ ∈ ( eqltrG ‘ 𝐺 ) ↔ ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrG ‘ 𝐺 ) ⟨“ 𝐵 𝐶 𝐴 ”⟩ ) )
15 13 14 mpbird ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ∈ ( eqltrG ‘ 𝐺 ) )