Metamath Proof Explorer


Theorem isghmd

Description: Deduction for a group homomorphism. (Contributed by Stefan O'Rear, 4-Feb-2015)

Ref Expression
Hypotheses isghmd.x ⊢ X = Base S
isghmd.y ⊢ Y = Base T
isghmd.a ⊢ + ˙ = + S
isghmd.b ⊢ ⨣ ˙ = + T
isghmd.s ⊢ φ → S ∈ Grp
isghmd.t ⊢ φ → T ∈ Grp
isghmd.f ⊢ φ → F : X ⟶ Y
isghmd.l ⊢ φ ∧ x ∈ X ∧ y ∈ X → F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
Assertion isghmd ⊢ φ → F ∈ S GrpHom T

Proof

Step Hyp Ref Expression
1 isghmd.x ⊢ X = Base S
2 isghmd.y ⊢ Y = Base T
3 isghmd.a ⊢ + ˙ = + S
4 isghmd.b ⊢ ⨣ ˙ = + T
5 isghmd.s ⊢ φ → S ∈ Grp
6 isghmd.t ⊢ φ → T ∈ Grp
7 isghmd.f ⊢ φ → F : X ⟶ Y
8 isghmd.l ⊢ φ ∧ x ∈ X ∧ y ∈ X → F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
9 8 ralrimivva ⊢ φ → ∀ x ∈ X ∀ y ∈ X F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
10 7 9 jca ⊢ φ → F : X ⟶ Y ∧ ∀ x ∈ X ∀ y ∈ X F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
11 1 2 3 4 isghm ⊢ F ∈ S GrpHom T ↔ S ∈ Grp ∧ T ∈ Grp ∧ F : X ⟶ Y ∧ ∀ x ∈ X ∀ y ∈ X F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
12 5 6 10 11 syl21anbrc ⊢ φ → F ∈ S GrpHom T