Metamath Proof Explorer


Theorem itgeq2dv

Description: Equality theorem for an integral. (Contributed by Mario Carneiro, 7-Jul-2014)

Ref Expression
Hypothesis itgeq2dv.1 ⊢ φ ∧ x ∈ A → B = C
Assertion itgeq2dv ⊢ φ → ∫ A B dx = ∫ A C dx

Proof

Step Hyp Ref Expression
1 itgeq2dv.1 ⊢ φ ∧ x ∈ A → B = C
2 1 ralrimiva ⊢ φ → ∀ x ∈ A B = C
3 itgeq2 ⊢ ∀ x ∈ A B = C → ∫ A B dx = ∫ A C dx
4 2 3 syl ⊢ φ → ∫ A B dx = ∫ A C dx