Metamath Proof Explorer


Theorem lazval

Description: An adjunction of a complex number to the ring of integers. (Contributed by AV, 24-Oct-2026)

Ref Expression
Assertion lazval Could not format assertion : No typesetting found for |- ( S e. CC -> ( Z[]l ` S ) = { x e. CC | E. a e. ZZ E. b e. ZZ x = ( a + ( b x. S ) ) } ) with typecode |-

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ s = S → b ⁢ s = b ⁢ S
2 1 oveq2d ⊢ s = S → a + b ⁢ s = a + b ⁢ S
3 2 eqeq2d ⊢ s = S → x = a + b ⁢ s ↔ x = a + b ⁢ S
4 3 2rexbidv ⊢ s = S → ∃ a ∈ ℤ ∃ b ∈ ℤ x = a + b ⁢ s ↔ ∃ a ∈ ℤ ∃ b ∈ ℤ x = a + b ⁢ S
5 4 rabbidv ⊢ s = S → x ∈ ℂ | ∃ a ∈ ℤ ∃ b ∈ ℤ x = a + b ⁢ s = x ∈ ℂ | ∃ a ∈ ℤ ∃ b ∈ ℤ x = a + b ⁢ S
6 df-laz Could not format Z[]l = ( s e. CC |-> { x e. CC | E. a e. ZZ E. b e. ZZ x = ( a + ( b x. s ) ) } ) : No typesetting found for |- Z[]l = ( s e. CC |-> { x e. CC | E. a e. ZZ E. b e. ZZ x = ( a + ( b x. s ) ) } ) with typecode |-
7 cnex ⊢ ℂ ∈ V
8 7 rabex ⊢ x ∈ ℂ | ∃ a ∈ ℤ ∃ b ∈ ℤ x = a + b ⁢ S ∈ V
9 5 6 8 fvmpt Could not format ( S e. CC -> ( Z[]l ` S ) = { x e. CC | E. a e. ZZ E. b e. ZZ x = ( a + ( b x. S ) ) } ) : No typesetting found for |- ( S e. CC -> ( Z[]l ` S ) = { x e. CC | E. a e. ZZ E. b e. ZZ x = ( a + ( b x. S ) ) } ) with typecode |-