Metamath Proof Explorer


Theorem lazval

Description: An adjunction of a complex number to the ring of integers. (Contributed by AV, 24-Oct-2026)

Ref Expression
Assertion lazval ( 𝑆 ∈ ℂ → ( Z[]l ‘ 𝑆 ) = { 𝑥 ∈ ℂ ∣ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) } )

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ ( 𝑠 = 𝑆 → ( 𝑏 · 𝑠 ) = ( 𝑏 · 𝑆 ) )
2 1 oveq2d ⊢ ( 𝑠 = 𝑆 → ( 𝑎 + ( 𝑏 · 𝑠 ) ) = ( 𝑎 + ( 𝑏 · 𝑆 ) ) )
3 2 eqeq2d ⊢ ( 𝑠 = 𝑆 → ( 𝑥 = ( 𝑎 + ( 𝑏 · 𝑠 ) ) ↔ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) ) )
4 3 2rexbidv ⊢ ( 𝑠 = 𝑆 → ( ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑠 ) ) ↔ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) ) )
5 4 rabbidv ⊢ ( 𝑠 = 𝑆 → { 𝑥 ∈ ℂ ∣ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑠 ) ) } = { 𝑥 ∈ ℂ ∣ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) } )
6 df-laz ⊢ Z[]l = ( 𝑠 ∈ ℂ ↦ { 𝑥 ∈ ℂ ∣ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑠 ) ) } )
7 cnex ⊢ ℂ ∈ V
8 7 rabex ⊢ { 𝑥 ∈ ℂ ∣ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) } ∈ V
9 5 6 8 fvmpt ⊢ ( 𝑆 ∈ ℂ → ( Z[]l ‘ 𝑆 ) = { 𝑥 ∈ ℂ ∣ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑥 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) } )