Metamath Proof Explorer


Theorem leabss

Description: A surreal is less than or equal to its absolute value. (Contributed by Scott Fenton, 16-Apr-2025)

Ref Expression
Assertion leabss ⊢ A ∈ No → A ≤ s abs s ⁡ A

Proof

Step Hyp Ref Expression
1 lesid ⊢ A ∈ No → A ≤ s A
2 1 adantr ⊢ A ∈ No ∧ 0 s ≤ s A → A ≤ s A
3 abssid ⊢ A ∈ No ∧ 0 s ≤ s A → abs s ⁡ A = A
4 2 3 breqtrrd ⊢ A ∈ No ∧ 0 s ≤ s A → A ≤ s abs s ⁡ A
5 simpl ⊢ A ∈ No ∧ A ≤ s 0 s → A ∈ No
6 0no ⊢ 0 s ∈ No
7 6 a1i ⊢ A ∈ No ∧ A ≤ s 0 s → 0 s ∈ No
8 negscl ⊢ A ∈ No → + s ⁡ A ∈ No
9 8 adantr ⊢ A ∈ No ∧ A ≤ s 0 s → + s ⁡ A ∈ No
10 simpr ⊢ A ∈ No ∧ A ≤ s 0 s → A ≤ s 0 s
11 neg0s ⊢ + s ⁡ 0 s = 0 s
12 5 7 lenegsd ⊢ A ∈ No ∧ A ≤ s 0 s → A ≤ s 0 s ↔ + s ⁡ 0 s ≤ s + s ⁡ A
13 10 12 mpbid ⊢ A ∈ No ∧ A ≤ s 0 s → + s ⁡ 0 s ≤ s + s ⁡ A
14 11 13 eqbrtrrid ⊢ A ∈ No ∧ A ≤ s 0 s → 0 s ≤ s + s ⁡ A
15 5 7 9 10 14 lestrd ⊢ A ∈ No ∧ A ≤ s 0 s → A ≤ s + s ⁡ A
16 abssnid ⊢ A ∈ No ∧ A ≤ s 0 s → abs s ⁡ A = + s ⁡ A
17 15 16 breqtrrd ⊢ A ∈ No ∧ A ≤ s 0 s → A ≤ s abs s ⁡ A
18 lestric ⊢ 0 s ∈ No ∧ A ∈ No → 0 s ≤ s A ∨ A ≤ s 0 s
19 6 18 mpan ⊢ A ∈ No → 0 s ≤ s A ∨ A ≤ s 0 s
20 4 17 19 mpjaodan ⊢ A ∈ No → A ≤ s abs s ⁡ A