Metamath Proof Explorer


Theorem leexp2rd

Description: Ordering relationship for exponentiation. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypotheses sqgt0d.1 ⊢ φ → A ∈ ℝ
leexp2rd.2 ⊢ φ → M ∈ ℕ 0
leexp2rd.3 ⊢ φ → N ∈ ℤ ≥ M
leexp2rd.4 ⊢ φ → 0 ≤ A
leexp2rd.5 ⊢ φ → A ≤ 1
Assertion leexp2rd ⊢ φ → A N ≤ A M

Proof

Step Hyp Ref Expression
1 sqgt0d.1 ⊢ φ → A ∈ ℝ
2 leexp2rd.2 ⊢ φ → M ∈ ℕ 0
3 leexp2rd.3 ⊢ φ → N ∈ ℤ ≥ M
4 leexp2rd.4 ⊢ φ → 0 ≤ A
5 leexp2rd.5 ⊢ φ → A ≤ 1
6 leexp2r ⊢ A ∈ ℝ ∧ M ∈ ℕ 0 ∧ N ∈ ℤ ≥ M ∧ 0 ≤ A ∧ A ≤ 1 → A N ≤ A M
7 1 2 3 4 5 6 syl32anc ⊢ φ → A N ≤ A M