Metamath Proof Explorer


Theorem linindsi

Description: The implications of being a linearly independent subset. (Contributed by AV, 13-Apr-2019) (Revised by AV, 30-Jul-2019)

Ref Expression
Hypotheses islininds.b ⊢ B = Base M
islininds.z ⊢ Z = 0 M
islininds.r ⊢ R = Scalar ⁡ M
islininds.e ⊢ E = Base R
islininds.0 ⊢ 0 ˙ = 0 R
Assertion linindsi ⊢ S linIndS M → S ∈ 𝒫 B ∧ ∀ f ∈ E S finSupp 0 ˙⁡ f ∧ f linC ⁡ M S = Z → ∀ x ∈ S f ⁡ x = 0 ˙

Proof

Step Hyp Ref Expression
1 islininds.b ⊢ B = Base M
2 islininds.z ⊢ Z = 0 M
3 islininds.r ⊢ R = Scalar ⁡ M
4 islininds.e ⊢ E = Base R
5 islininds.0 ⊢ 0 ˙ = 0 R
6 linindsv ⊢ S linIndS M → S ∈ V ∧ M ∈ V
7 1 2 3 4 5 islininds ⊢ S ∈ V ∧ M ∈ V → S linIndS M ↔ S ∈ 𝒫 B ∧ ∀ f ∈ E S finSupp 0 ˙⁡ f ∧ f linC ⁡ M S = Z → ∀ x ∈ S f ⁡ x = 0 ˙
8 6 7 syl ⊢ S linIndS M → S linIndS M ↔ S ∈ 𝒫 B ∧ ∀ f ∈ E S finSupp 0 ˙⁡ f ∧ f linC ⁡ M S = Z → ∀ x ∈ S f ⁡ x = 0 ˙
9 8 ibi ⊢ S linIndS M → S ∈ 𝒫 B ∧ ∀ f ∈ E S finSupp 0 ˙⁡ f ∧ f linC ⁡ M S = Z → ∀ x ∈ S f ⁡ x = 0 ˙