Metamath Proof Explorer


Theorem lplnneat

Description: No lattice plane is an atom. (Contributed by NM, 15-Jul-2012)

Ref Expression
Hypotheses lplnneat.a ⊢ A = Atoms ⁡ K
lplnneat.p ⊢ P = LPlanes ⁡ K
Assertion lplnneat ⊢ K ∈ HL ∧ X ∈ P → ¬ X ∈ A

Proof

Step Hyp Ref Expression
1 lplnneat.a ⊢ A = Atoms ⁡ K
2 lplnneat.p ⊢ P = LPlanes ⁡ K
3 hllat ⊢ K ∈ HL → K ∈ Lat
4 eqid ⊢ Base K = Base K
5 4 2 lplnbase ⊢ X ∈ P → X ∈ Base K
6 eqid ⊢ ≤ K = ≤ K
7 4 6 latref ⊢ K ∈ Lat ∧ X ∈ Base K → X ≤ K X
8 3 5 7 syl2an ⊢ K ∈ HL ∧ X ∈ P → X ≤ K X
9 6 1 2 lplnnleat ⊢ K ∈ HL ∧ X ∈ P ∧ X ∈ A → ¬ X ≤ K X
10 9 3expia ⊢ K ∈ HL ∧ X ∈ P → X ∈ A → ¬ X ≤ K X
11 8 10 mt2d ⊢ K ∈ HL ∧ X ∈ P → ¬ X ∈ A