Metamath Proof Explorer


Theorem lspprid1

Description: A member of a pair of vectors belongs to their span. (Contributed by NM, 14-May-2015)

Ref Expression
Hypotheses lspprid.v ⊢ V = Base W
lspprid.n ⊢ N = LSpan ⁡ W
lspprid.w ⊢ φ → W ∈ LMod
lspprid.x ⊢ φ → X ∈ V
lspprid.y ⊢ φ → Y ∈ V
Assertion lspprid1 ⊢ φ → X ∈ N ⁡ X Y

Proof

Step Hyp Ref Expression
1 lspprid.v ⊢ V = Base W
2 lspprid.n ⊢ N = LSpan ⁡ W
3 lspprid.w ⊢ φ → W ∈ LMod
4 lspprid.x ⊢ φ → X ∈ V
5 lspprid.y ⊢ φ → Y ∈ V
6 4 5 prssd ⊢ φ → X Y ⊆ V
7 snsspr1 ⊢ X ⊆ X Y
8 7 a1i ⊢ φ → X ⊆ X Y
9 1 2 lspss ⊢ W ∈ LMod ∧ X Y ⊆ V ∧ X ⊆ X Y → N ⁡ X ⊆ N ⁡ X Y
10 3 6 8 9 syl3anc ⊢ φ → N ⁡ X ⊆ N ⁡ X Y
11 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
12 1 11 2 3 4 5 lspprcl ⊢ φ → N ⁡ X Y ∈ LSubSp ⁡ W
13 1 11 2 3 12 4 ellspsn5b ⊢ φ → X ∈ N ⁡ X Y ↔ N ⁡ X ⊆ N ⁡ X Y
14 10 13 mpbird ⊢ φ → X ∈ N ⁡ X Y