Metamath Proof Explorer


Theorem lspsnss2

Description: Comparable spans of singletons must have proportional vectors. See lspsneq for equal span version. (Contributed by NM, 7-Jun-2015)

Ref Expression
Hypotheses lspsnss2.v ⊢ V = Base W
lspsnss2.s ⊢ S = Scalar ⁡ W
lspsnss2.k ⊢ K = Base S
lspsnss2.t ⊢ · ˙ = ⋅ W
lspsnss2.n ⊢ N = LSpan ⁡ W
lspsnss2.w ⊢ φ → W ∈ LMod
lspsnss2.x ⊢ φ → X ∈ V
lspsnss2.y ⊢ φ → Y ∈ V
Assertion lspsnss2 ⊢ φ → N ⁡ X ⊆ N ⁡ Y ↔ ∃ k ∈ K X = k · ˙ Y

Proof

Step Hyp Ref Expression
1 lspsnss2.v ⊢ V = Base W
2 lspsnss2.s ⊢ S = Scalar ⁡ W
3 lspsnss2.k ⊢ K = Base S
4 lspsnss2.t ⊢ · ˙ = ⋅ W
5 lspsnss2.n ⊢ N = LSpan ⁡ W
6 lspsnss2.w ⊢ φ → W ∈ LMod
7 lspsnss2.x ⊢ φ → X ∈ V
8 lspsnss2.y ⊢ φ → Y ∈ V
9 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
10 1 9 5 lspsncl ⊢ W ∈ LMod ∧ Y ∈ V → N ⁡ Y ∈ LSubSp ⁡ W
11 6 8 10 syl2anc ⊢ φ → N ⁡ Y ∈ LSubSp ⁡ W
12 1 9 5 6 11 7 ellspsn5b ⊢ φ → X ∈ N ⁡ Y ↔ N ⁡ X ⊆ N ⁡ Y
13 2 3 1 4 5 ellspsn ⊢ W ∈ LMod ∧ Y ∈ V → X ∈ N ⁡ Y ↔ ∃ k ∈ K X = k · ˙ Y
14 6 8 13 syl2anc ⊢ φ → X ∈ N ⁡ Y ↔ ∃ k ∈ K X = k · ˙ Y
15 12 14 bitr3d ⊢ φ → N ⁡ X ⊆ N ⁡ Y ↔ ∃ k ∈ K X = k · ˙ Y