Metamath Proof Explorer


Theorem ltrncl

Description: Closure of a lattice translation. (Contributed by NM, 20-May-2012)

Ref Expression
Hypotheses ltrn1o.b ⊢ B = Base K
ltrn1o.h ⊢ H = LHyp ⁡ K
ltrn1o.t ⊢ T = LTrn ⁡ K ⁡ W
Assertion ltrncl ⊢ K ∈ V ∧ W ∈ H ∧ F ∈ T ∧ X ∈ B → F ⁡ X ∈ B

Proof

Step Hyp Ref Expression
1 ltrn1o.b ⊢ B = Base K
2 ltrn1o.h ⊢ H = LHyp ⁡ K
3 ltrn1o.t ⊢ T = LTrn ⁡ K ⁡ W
4 simp1l ⊢ K ∈ V ∧ W ∈ H ∧ F ∈ T ∧ X ∈ B → K ∈ V
5 eqid ⊢ LAut ⁡ K = LAut ⁡ K
6 2 5 3 ltrnlaut ⊢ K ∈ V ∧ W ∈ H ∧ F ∈ T → F ∈ LAut ⁡ K
7 6 3adant3 ⊢ K ∈ V ∧ W ∈ H ∧ F ∈ T ∧ X ∈ B → F ∈ LAut ⁡ K
8 simp3 ⊢ K ∈ V ∧ W ∈ H ∧ F ∈ T ∧ X ∈ B → X ∈ B
9 1 5 lautcl ⊢ K ∈ V ∧ F ∈ LAut ⁡ K ∧ X ∈ B → F ⁡ X ∈ B
10 4 7 8 9 syl21anc ⊢ K ∈ V ∧ W ∈ H ∧ F ∈ T ∧ X ∈ B → F ⁡ X ∈ B