Metamath Proof Explorer


Theorem ltsub1dd

Description: Subtraction from both sides of 'less than'. (Contributed by Mario Carneiro, 30-May-2016)

Ref Expression
Hypotheses leidd.1 ⊢ φ → A ∈ ℝ
ltnegd.2 ⊢ φ → B ∈ ℝ
ltadd1d.3 ⊢ φ → C ∈ ℝ
ltadd1dd.4 ⊢ φ → A < B
Assertion ltsub1dd ⊢ φ → A − C < B − C

Proof

Step Hyp Ref Expression
1 leidd.1 ⊢ φ → A ∈ ℝ
2 ltnegd.2 ⊢ φ → B ∈ ℝ
3 ltadd1d.3 ⊢ φ → C ∈ ℝ
4 ltadd1dd.4 ⊢ φ → A < B
5 1 2 3 ltsub1d ⊢ φ → A < B ↔ A − C < B − C
6 4 5 mpbid ⊢ φ → A − C < B − C