Metamath Proof Explorer


Theorem ltsub1d

Description: Subtraction from both sides of 'less than'. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses leidd.1 ⊢ φ → A ∈ ℝ
ltnegd.2 ⊢ φ → B ∈ ℝ
ltadd1d.3 ⊢ φ → C ∈ ℝ
Assertion ltsub1d ⊢ φ → A < B ↔ A − C < B − C

Proof

Step Hyp Ref Expression
1 leidd.1 ⊢ φ → A ∈ ℝ
2 ltnegd.2 ⊢ φ → B ∈ ℝ
3 ltadd1d.3 ⊢ φ → C ∈ ℝ
4 ltsub1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ → A < B ↔ A − C < B − C
5 1 2 3 4 syl3anc ⊢ φ → A < B ↔ A − C < B − C