Metamath Proof Explorer


Theorem ltsubadd2d

Description: 'Less than' relationship between subtraction and addition. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses leidd.1 ⊢ φ → A ∈ ℝ
ltnegd.2 ⊢ φ → B ∈ ℝ
ltadd1d.3 ⊢ φ → C ∈ ℝ
Assertion ltsubadd2d ⊢ φ → A − B < C ↔ A < B + C

Proof

Step Hyp Ref Expression
1 leidd.1 ⊢ φ → A ∈ ℝ
2 ltnegd.2 ⊢ φ → B ∈ ℝ
3 ltadd1d.3 ⊢ φ → C ∈ ℝ
4 ltsubadd2 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ → A − B < C ↔ A < B + C
5 1 2 3 4 syl3anc ⊢ φ → A − B < C ↔ A < B + C