Metamath Proof Explorer


Theorem met2ndc

Description: A metric space is second-countable iff it is separable (has a countable dense subset). (Contributed by Mario Carneiro, 13-Apr-2015)

Ref Expression
Hypothesis methaus.1 ⊢ J = MetOpen ⁡ D
Assertion met2ndc ⊢ D ∈ ∞Met ⁡ X → J ∈ 2 nd 𝜔 ↔ ∃ x ∈ 𝒫 X x ≼ ω ∧ cls ⁡ J ⁡ x = X

Proof

Step Hyp Ref Expression
1 methaus.1 ⊢ J = MetOpen ⁡ D
2 eqid ⊢ ⋃ J = ⋃ J
3 2 2ndcsep ⊢ J ∈ 2 nd 𝜔 → ∃ x ∈ 𝒫 ⋃ J x ≼ ω ∧ cls ⁡ J ⁡ x = ⋃ J
4 1 mopnuni ⊢ D ∈ ∞Met ⁡ X → X = ⋃ J
5 4 pweqd ⊢ D ∈ ∞Met ⁡ X → 𝒫 X = 𝒫 ⋃ J
6 4 eqeq2d ⊢ D ∈ ∞Met ⁡ X → cls ⁡ J ⁡ x = X ↔ cls ⁡ J ⁡ x = ⋃ J
7 6 anbi2d ⊢ D ∈ ∞Met ⁡ X → x ≼ ω ∧ cls ⁡ J ⁡ x = X ↔ x ≼ ω ∧ cls ⁡ J ⁡ x = ⋃ J
8 5 7 rexeqbidv ⊢ D ∈ ∞Met ⁡ X → ∃ x ∈ 𝒫 X x ≼ ω ∧ cls ⁡ J ⁡ x = X ↔ ∃ x ∈ 𝒫 ⋃ J x ≼ ω ∧ cls ⁡ J ⁡ x = ⋃ J
9 3 8 imbitrrid ⊢ D ∈ ∞Met ⁡ X → J ∈ 2 nd 𝜔 → ∃ x ∈ 𝒫 X x ≼ ω ∧ cls ⁡ J ⁡ x = X
10 elpwi ⊢ x ∈ 𝒫 X → x ⊆ X
11 1 met2ndci ⊢ D ∈ ∞Met ⁡ X ∧ x ⊆ X ∧ x ≼ ω ∧ cls ⁡ J ⁡ x = X → J ∈ 2 nd 𝜔
12 11 3exp2 ⊢ D ∈ ∞Met ⁡ X → x ⊆ X → x ≼ ω → cls ⁡ J ⁡ x = X → J ∈ 2 nd 𝜔
13 12 imp4a ⊢ D ∈ ∞Met ⁡ X → x ⊆ X → x ≼ ω ∧ cls ⁡ J ⁡ x = X → J ∈ 2 nd 𝜔
14 10 13 syl5 ⊢ D ∈ ∞Met ⁡ X → x ∈ 𝒫 X → x ≼ ω ∧ cls ⁡ J ⁡ x = X → J ∈ 2 nd 𝜔
15 14 rexlimdv ⊢ D ∈ ∞Met ⁡ X → ∃ x ∈ 𝒫 X x ≼ ω ∧ cls ⁡ J ⁡ x = X → J ∈ 2 nd 𝜔
16 9 15 impbid ⊢ D ∈ ∞Met ⁡ X → J ∈ 2 nd 𝜔 ↔ ∃ x ∈ 𝒫 X x ≼ ω ∧ cls ⁡ J ⁡ x = X