Metamath Proof Explorer


Theorem mptcnv

Description: The converse of a mapping function. (Contributed by Thierry Arnoux, 16-Jan-2017)

Ref Expression
Hypothesis mptcnv.1 ⊢ φ → x ∈ A ∧ y = B ↔ y ∈ C ∧ x = D
Assertion mptcnv ⊢ φ → x ∈ A ⟼ B -1 = y ∈ C ⟼ D

Proof

Step Hyp Ref Expression
1 mptcnv.1 ⊢ φ → x ∈ A ∧ y = B ↔ y ∈ C ∧ x = D
2 1 opabbidv ⊢ φ → y x | x ∈ A ∧ y = B = y x | y ∈ C ∧ x = D
3 df-mpt ⊢ x ∈ A ⟼ B = x y | x ∈ A ∧ y = B
4 3 cnveqi ⊢ x ∈ A ⟼ B -1 = x y | x ∈ A ∧ y = B -1
5 cnvopab ⊢ x y | x ∈ A ∧ y = B -1 = y x | x ∈ A ∧ y = B
6 4 5 eqtri ⊢ x ∈ A ⟼ B -1 = y x | x ∈ A ∧ y = B
7 df-mpt ⊢ y ∈ C ⟼ D = y x | y ∈ C ∧ x = D
8 2 6 7 3eqtr4g ⊢ φ → x ∈ A ⟼ B -1 = y ∈ C ⟼ D