Metamath Proof Explorer


Theorem mulrid

Description: The number 1 is an identity element for multiplication. Based on ideas by Eric Schmidt. (Contributed by Scott Fenton, 3-Jan-2013)

Ref Expression
Assertion mulrid ⊢ A ∈ ℂ → A ⋅ 1 = A

Proof

Step Hyp Ref Expression
1 cnre ⊢ A ∈ ℂ → ∃ x ∈ ℝ ∃ y ∈ ℝ A = x + i ⁢ y
2 recn ⊢ x ∈ ℝ → x ∈ ℂ
3 ax-icn ⊢ i ∈ ℂ
4 recn ⊢ y ∈ ℝ → y ∈ ℂ
5 mulcl ⊢ i ∈ ℂ ∧ y ∈ ℂ → i ⁢ y ∈ ℂ
6 3 4 5 sylancr ⊢ y ∈ ℝ → i ⁢ y ∈ ℂ
7 ax-1cn ⊢ 1 ∈ ℂ
8 adddir ⊢ x ∈ ℂ ∧ i ⁢ y ∈ ℂ ∧ 1 ∈ ℂ → x + i ⁢ y ⋅ 1 = x ⋅ 1 + i ⁢ y ⋅ 1
9 7 8 mp3an3 ⊢ x ∈ ℂ ∧ i ⁢ y ∈ ℂ → x + i ⁢ y ⋅ 1 = x ⋅ 1 + i ⁢ y ⋅ 1
10 2 6 9 syl2an ⊢ x ∈ ℝ ∧ y ∈ ℝ → x + i ⁢ y ⋅ 1 = x ⋅ 1 + i ⁢ y ⋅ 1
11 ax-1rid ⊢ x ∈ ℝ → x ⋅ 1 = x
12 mulass ⊢ i ∈ ℂ ∧ y ∈ ℂ ∧ 1 ∈ ℂ → i ⁢ y ⋅ 1 = i ⁢ y ⋅ 1
13 3 7 12 mp3an13 ⊢ y ∈ ℂ → i ⁢ y ⋅ 1 = i ⁢ y ⋅ 1
14 4 13 syl ⊢ y ∈ ℝ → i ⁢ y ⋅ 1 = i ⁢ y ⋅ 1
15 ax-1rid ⊢ y ∈ ℝ → y ⋅ 1 = y
16 15 oveq2d ⊢ y ∈ ℝ → i ⁢ y ⋅ 1 = i ⁢ y
17 14 16 eqtrd ⊢ y ∈ ℝ → i ⁢ y ⋅ 1 = i ⁢ y
18 11 17 oveqan12d ⊢ x ∈ ℝ ∧ y ∈ ℝ → x ⋅ 1 + i ⁢ y ⋅ 1 = x + i ⁢ y
19 10 18 eqtrd ⊢ x ∈ ℝ ∧ y ∈ ℝ → x + i ⁢ y ⋅ 1 = x + i ⁢ y
20 oveq1 ⊢ A = x + i ⁢ y → A ⋅ 1 = x + i ⁢ y ⋅ 1
21 id ⊢ A = x + i ⁢ y → A = x + i ⁢ y
22 20 21 eqeq12d ⊢ A = x + i ⁢ y → A ⋅ 1 = A ↔ x + i ⁢ y ⋅ 1 = x + i ⁢ y
23 19 22 syl5ibrcom ⊢ x ∈ ℝ ∧ y ∈ ℝ → A = x + i ⁢ y → A ⋅ 1 = A
24 23 rexlimivv ⊢ ∃ x ∈ ℝ ∃ y ∈ ℝ A = x + i ⁢ y → A ⋅ 1 = A
25 1 24 syl ⊢ A ∈ ℂ → A ⋅ 1 = A