Metamath Proof Explorer


Theorem negeqd

Description: Equality deduction for negatives. (Contributed by NM, 14-May-1999)

Ref Expression
Hypothesis negeqd.1 φ A = B
Assertion negeqd φ A = B

Proof

Step Hyp Ref Expression
1 negeqd.1 φ A = B
2 negeq A = B A = B
3 1 2 syl φ A = B