Metamath Proof Explorer


Theorem negsubi

Description: Relationship between subtraction and negative. Theorem I.3 of Apostol p. 18. (Contributed by NM, 26-Nov-1994) (Proof shortened by Andrew Salmon, 22-Oct-2011)

Ref Expression
Hypotheses negidi.1 ⊢ A ∈ ℂ
pncan3i.2 ⊢ B ∈ ℂ
Assertion negsubi ⊢ A + − B = A − B

Proof

Step Hyp Ref Expression
1 negidi.1 ⊢ A ∈ ℂ
2 pncan3i.2 ⊢ B ∈ ℂ
3 negsub ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + − B = A − B
4 1 2 3 mp2an ⊢ A + − B = A − B