Metamath Proof Explorer


Theorem nfs1

Description: If y is not free in ph , x is not free in [ y / x ] ph . Usage of this theorem is discouraged because it depends on ax-13 . Check out nfs1v for a version requiring fewer axioms. (Contributed by Mario Carneiro, 11-Aug-2016) (New usage is discouraged.)

Ref Expression
Hypothesis nfs1.1 ⊢ Ⅎ y φ
Assertion nfs1 ⊢ Ⅎ x y x φ

Proof

Step Hyp Ref Expression
1 nfs1.1 ⊢ Ⅎ y φ
2 1 nf5ri ⊢ φ → ∀ y φ
3 2 hbsb3 ⊢ y x φ → ∀ x y x φ
4 3 nf5i ⊢ Ⅎ x y x φ