Metamath Proof Explorer
Description: Extending a linear order to subsets, the empty set is less than itself.
Note in Alling, p. 3. (Contributed by RP, 28-Nov-2023)
|
|
Ref |
Expression |
|
Hypothesis |
nla0001.defsslt |
|
|
Assertion |
nla0001 |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
nla0001.defsslt |
|
| 2 |
|
0ex |
|
| 3 |
2
|
a1i |
|
| 4 |
|
0ss |
|
| 5 |
4
|
a1i |
|
| 6 |
1 3 5
|
nla0002 |
|