Metamath Proof Explorer
Description: Extending a linear order to subsets, the empty set is less than itself.
Note in Alling, p. 3. (Contributed by RP, 28-Nov-2023)
|
|
Ref |
Expression |
|
Hypothesis |
nla0001.defsslt |
⊢ < = { 〈 𝑎 , 𝑏 〉 ∣ ( 𝑎 ⊆ 𝑆 ∧ 𝑏 ⊆ 𝑆 ∧ ∀ 𝑥 ∈ 𝑎 ∀ 𝑦 ∈ 𝑏 𝑥 𝑅 𝑦 ) } |
|
Assertion |
nla0001 |
⊢ ( 𝜑 → ∅ < ∅ ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
nla0001.defsslt |
⊢ < = { 〈 𝑎 , 𝑏 〉 ∣ ( 𝑎 ⊆ 𝑆 ∧ 𝑏 ⊆ 𝑆 ∧ ∀ 𝑥 ∈ 𝑎 ∀ 𝑦 ∈ 𝑏 𝑥 𝑅 𝑦 ) } |
2 |
|
0ex |
⊢ ∅ ∈ V |
3 |
2
|
a1i |
⊢ ( 𝜑 → ∅ ∈ V ) |
4 |
|
0ss |
⊢ ∅ ⊆ 𝑆 |
5 |
4
|
a1i |
⊢ ( 𝜑 → ∅ ⊆ 𝑆 ) |
6 |
1 3 5
|
nla0002 |
⊢ ( 𝜑 → ∅ < ∅ ) |