Metamath Proof Explorer


Theorem nla0001

Description: Extending a linear order to subsets, the empty set is less than itself. Note in Alling, p. 3. (Contributed by RP, 28-Nov-2023)

Ref Expression
Hypothesis nla0001.defsslt <˙=ab|aSbSxaybxRy
Assertion nla0001 φ<˙

Proof

Step Hyp Ref Expression
1 nla0001.defsslt <˙=ab|aSbSxaybxRy
2 0ex V
3 2 a1i φV
4 0ss S
5 4 a1i φS
6 1 3 5 nla0002 φ<˙