Metamath Proof Explorer


Theorem nnssi2

Description: Convert a theorem for real/complex numbers into one for positive integers. (Contributed by Jeff Hoffman, 17-Jun-2008)

Ref Expression
Hypotheses nnssi2.1 ⊢ ℕ ⊆ D
nnssi2.2 ⊢ B ∈ ℕ → φ
nnssi2.3 ⊢ A ∈ D ∧ B ∈ D ∧ φ → ψ
Assertion nnssi2 ⊢ A ∈ ℕ ∧ B ∈ ℕ → ψ

Proof

Step Hyp Ref Expression
1 nnssi2.1 ⊢ ℕ ⊆ D
2 nnssi2.2 ⊢ B ∈ ℕ → φ
3 nnssi2.3 ⊢ A ∈ D ∧ B ∈ D ∧ φ → ψ
4 1 sseli ⊢ A ∈ ℕ → A ∈ D
5 1 sseli ⊢ B ∈ ℕ → B ∈ D
6 4 5 2 3anim123i ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ B ∈ ℕ → A ∈ D ∧ B ∈ D ∧ φ
7 6 3anidm23 ⊢ A ∈ ℕ ∧ B ∈ ℕ → A ∈ D ∧ B ∈ D ∧ φ
8 7 3 syl ⊢ A ∈ ℕ ∧ B ∈ ℕ → ψ