Metamath Proof Explorer


Theorem nvm

Description: Vector subtraction in terms of group division operation. (Contributed by NM, 15-Feb-2008) (New usage is discouraged.)

Ref Expression
Hypotheses nvm.1 ⊢ X = BaseSet ⁡ U
nvm.2 ⊢ G = + v ⁡ U
nvm.3 ⊢ M = - v ⁡ U
nvm.6 ⊢ N = / g ⁡ G
Assertion nvm ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ X → A M B = A N B

Proof

Step Hyp Ref Expression
1 nvm.1 ⊢ X = BaseSet ⁡ U
2 nvm.2 ⊢ G = + v ⁡ U
3 nvm.3 ⊢ M = - v ⁡ U
4 nvm.6 ⊢ N = / g ⁡ G
5 2 3 vsfval ⊢ M = / g ⁡ G
6 5 4 eqtr4i ⊢ M = N
7 6 oveqi ⊢ A M B = A N B
8 7 a1i ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ X → A M B = A N B