Metamath Proof Explorer


Theorem oa1suc

Description: Addition with 1 is same as successor. Proposition 4.34(a) of Mendelson p. 266. (Contributed by NM, 29-Oct-1995) (Revised by Mario Carneiro, 16-Nov-2014)

Ref Expression
Assertion oa1suc A On A + 𝑜 1 𝑜 = suc A

Proof

Step Hyp Ref Expression
1 df-1o 1 𝑜 = suc
2 1 oveq2i A + 𝑜 1 𝑜 = A + 𝑜 suc
3 peano1 ω
4 onasuc A On ω A + 𝑜 suc = suc A + 𝑜
5 3 4 mpan2 A On A + 𝑜 suc = suc A + 𝑜
6 2 5 syl5eq A On A + 𝑜 1 𝑜 = suc A + 𝑜
7 oa0 A On A + 𝑜 = A
8 suceq A + 𝑜 = A suc A + 𝑜 = suc A
9 7 8 syl A On suc A + 𝑜 = suc A
10 6 9 eqtrd A On A + 𝑜 1 𝑜 = suc A