Metamath Proof Explorer


Theorem omsson

Description: Omega is a subset of On . (Contributed by NM, 13-Jun-1994) (Proof shortened by Andrew Salmon, 27-Aug-2011)

Ref Expression
Assertion omsson ⊢ ω ⊆ On

Proof

Step Hyp Ref Expression
1 df-om ⊢ ω = x ∈ On | ∀ y Lim ⁡ y → x ∈ y
2 1 ssrab3 ⊢ ω ⊆ On