Metamath Proof Explorer


Theorem ssrab3

Description: Subclass relation for a restricted class abstraction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

Ref Expression
Hypothesis ssrab3.1 ⊢ B = x ∈ A | φ
Assertion ssrab3 ⊢ B ⊆ A

Proof

Step Hyp Ref Expression
1 ssrab3.1 ⊢ B = x ∈ A | φ
2 ssrab2 ⊢ x ∈ A | φ ⊆ A
3 1 2 eqsstri ⊢ B ⊆ A