Metamath Proof Explorer


Theorem ssrab2

Description: Subclass relation for a restricted class. (Contributed by NM, 19-Mar-1997) (Proof shortened by BJ and SN, 8-Aug-2024)

Ref Expression
Assertion ssrab2 ⊢ x ∈ A | φ ⊆ A

Proof

Step Hyp Ref Expression
1 elrabi ⊢ y ∈ x ∈ A | φ → y ∈ A
2 1 ssriv ⊢ x ∈ A | φ ⊆ A