Metamath Proof Explorer


Theorem onfrALTlem1

Description: Lemma for onfrALT . (Contributed by Alan Sare, 22-Jul-2012) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion onfrALTlem1 ⊢ a ⊆ On ∧ a ≠ ∅ → x ∈ a ∧ a ∩ x = ∅ → ∃ y ∈ a a ∩ y = ∅

Proof

Step Hyp Ref Expression
1 19.8a ⊢ x ∈ a ∧ a ∩ x = ∅ → ∃ x x ∈ a ∧ a ∩ x = ∅
2 1 a1i ⊢ a ⊆ On ∧ a ≠ ∅ → x ∈ a ∧ a ∩ x = ∅ → ∃ x x ∈ a ∧ a ∩ x = ∅
3 cbvexsv ⊢ ∃ x x ∈ a ∧ a ∩ x = ∅ ↔ ∃ y y x x ∈ a ∧ a ∩ x = ∅
4 2 3 imbitrdi ⊢ a ⊆ On ∧ a ≠ ∅ → x ∈ a ∧ a ∩ x = ∅ → ∃ y y x x ∈ a ∧ a ∩ x = ∅
5 sbsbc ⊢ y x x ∈ a ∧ a ∩ x = ∅ ↔ [˙y / x]˙ x ∈ a ∧ a ∩ x = ∅
6 onfrALTlem4 ⊢ [˙y / x]˙ x ∈ a ∧ a ∩ x = ∅ ↔ y ∈ a ∧ a ∩ y = ∅
7 5 6 bitri ⊢ y x x ∈ a ∧ a ∩ x = ∅ ↔ y ∈ a ∧ a ∩ y = ∅
8 7 exbii ⊢ ∃ y y x x ∈ a ∧ a ∩ x = ∅ ↔ ∃ y y ∈ a ∧ a ∩ y = ∅
9 4 8 imbitrdi ⊢ a ⊆ On ∧ a ≠ ∅ → x ∈ a ∧ a ∩ x = ∅ → ∃ y y ∈ a ∧ a ∩ y = ∅
10 df-rex ⊢ ∃ y ∈ a a ∩ y = ∅ ↔ ∃ y y ∈ a ∧ a ∩ y = ∅
11 9 10 imbitrrdi ⊢ a ⊆ On ∧ a ≠ ∅ → x ∈ a ∧ a ∩ x = ∅ → ∃ y ∈ a a ∩ y = ∅