Metamath Proof Explorer


Theorem onfrALTlem4

Description: Lemma for onfrALT . (Contributed by Alan Sare, 22-Jul-2012) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion onfrALTlem4 ⊢ [˙y / x]˙ x ∈ a ∧ a ∩ x = ∅ ↔ y ∈ a ∧ a ∩ y = ∅

Proof

Step Hyp Ref Expression
1 sbcan ⊢ [˙y / x]˙ x ∈ a ∧ a ∩ x = ∅ ↔ [˙y / x]˙ x ∈ a ∧ [˙y / x]˙ a ∩ x = ∅
2 sbcel1v ⊢ [˙y / x]˙ x ∈ a ↔ y ∈ a
3 vex ⊢ y ∈ V
4 sbceqg ⊢ y ∈ V → [˙y / x]˙ a ∩ x = ∅ ↔ ⦋ y / x⦌ a ∩ x = ⦋ y / x⦌ ∅
5 3 4 ax-mp ⊢ [˙y / x]˙ a ∩ x = ∅ ↔ ⦋ y / x⦌ a ∩ x = ⦋ y / x⦌ ∅
6 csbin ⊢ ⦋ y / x⦌ a ∩ x = ⦋ y / x⦌ a ∩ ⦋ y / x⦌ x
7 csbconstg ⊢ y ∈ V → ⦋ y / x⦌ a = a
8 3 7 ax-mp ⊢ ⦋ y / x⦌ a = a
9 csbvarg ⊢ y ∈ V → ⦋ y / x⦌ x = y
10 3 9 ax-mp ⊢ ⦋ y / x⦌ x = y
11 8 10 ineq12i ⊢ ⦋ y / x⦌ a ∩ ⦋ y / x⦌ x = a ∩ y
12 6 11 eqtri ⊢ ⦋ y / x⦌ a ∩ x = a ∩ y
13 csb0 ⊢ ⦋ y / x⦌ ∅ = ∅
14 12 13 eqeq12i ⊢ ⦋ y / x⦌ a ∩ x = ⦋ y / x⦌ ∅ ↔ a ∩ y = ∅
15 5 14 bitri ⊢ [˙y / x]˙ a ∩ x = ∅ ↔ a ∩ y = ∅
16 2 15 anbi12i ⊢ [˙y / x]˙ x ∈ a ∧ [˙y / x]˙ a ∩ x = ∅ ↔ y ∈ a ∧ a ∩ y = ∅
17 1 16 bitri ⊢ [˙y / x]˙ x ∈ a ∧ a ∩ x = ∅ ↔ y ∈ a ∧ a ∩ y = ∅