Metamath Proof Explorer


Theorem onltsd

Description: Less-than is the same as birthday comparison over surreal ordinals. Deduction version. (Contributed by Scott Fenton, 25-Feb-2026)

Ref Expression
Hypotheses onltsd.1 ⊢ φ → A ∈ On s
onltsd.2 ⊢ φ → B ∈ On s
Assertion onltsd ⊢ φ → A < s B ↔ bday ⁡ A ∈ bday ⁡ B

Proof

Step Hyp Ref Expression
1 onltsd.1 ⊢ φ → A ∈ On s
2 onltsd.2 ⊢ φ → B ∈ On s
3 onlts ⊢ A ∈ On s ∧ B ∈ On s → A < s B ↔ bday ⁡ A ∈ bday ⁡ B
4 1 2 3 syl2anc ⊢ φ → A < s B ↔ bday ⁡ A ∈ bday ⁡ B