Metamath Proof Explorer


Theorem opab0

Description: Empty ordered pair class abstraction. (Contributed by AV, 29-Oct-2021)

Ref Expression
Assertion opab0 ⊢ x y | φ = ∅ ↔ ∀ x ∀ y ¬ φ

Proof

Step Hyp Ref Expression
1 opabn0 ⊢ x y | φ ≠ ∅ ↔ ∃ x ∃ y φ
2 df-ne ⊢ x y | φ ≠ ∅ ↔ ¬ x y | φ = ∅
3 2exnaln ⊢ ∃ x ∃ y φ ↔ ¬ ∀ x ∀ y ¬ φ
4 1 2 3 3bitr3i ⊢ ¬ x y | φ = ∅ ↔ ¬ ∀ x ∀ y ¬ φ
5 4 con4bii ⊢ x y | φ = ∅ ↔ ∀ x ∀ y ¬ φ