Metamath Proof Explorer


Theorem opnneiss

Description: An open set is a neighborhood of any of its subsets. (Contributed by NM, 13-Feb-2007)

Ref Expression
Assertion opnneiss ⊢ J ∈ Top ∧ N ∈ J ∧ S ⊆ N → N ∈ nei ⁡ J ⁡ S

Proof

Step Hyp Ref Expression
1 simp3 ⊢ J ∈ Top ∧ N ∈ J ∧ S ⊆ N → S ⊆ N
2 eqid ⊢ ⋃ J = ⋃ J
3 2 eltopss ⊢ J ∈ Top ∧ N ∈ J → N ⊆ ⋃ J
4 sstr ⊢ S ⊆ N ∧ N ⊆ ⋃ J → S ⊆ ⋃ J
5 4 ancoms ⊢ N ⊆ ⋃ J ∧ S ⊆ N → S ⊆ ⋃ J
6 3 5 stoic3 ⊢ J ∈ Top ∧ N ∈ J ∧ S ⊆ N → S ⊆ ⋃ J
7 2 opnneissb ⊢ J ∈ Top ∧ N ∈ J ∧ S ⊆ ⋃ J → S ⊆ N ↔ N ∈ nei ⁡ J ⁡ S
8 6 7 syld3an3 ⊢ J ∈ Top ∧ N ∈ J ∧ S ⊆ N → S ⊆ N ↔ N ∈ nei ⁡ J ⁡ S
9 1 8 mpbid ⊢ J ∈ Top ∧ N ∈ J ∧ S ⊆ N → N ∈ nei ⁡ J ⁡ S