Metamath Proof Explorer


Theorem oppgleOLD

Description: Obsolete version of oppgle as of 27-Oct-2024. less-than relation of an opposite group. (Contributed by Thierry Arnoux, 13-Apr-2018) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses oppglt.1 O=opp𝑔R
oppgle.2 ˙=R
Assertion oppgleOLD ˙=O

Proof

Step Hyp Ref Expression
1 oppglt.1 O=opp𝑔R
2 oppgle.2 ˙=R
3 df-ple le=Slot10
4 10nn 10
5 2re 2
6 2lt10 2<10
7 5 6 gtneii 102
8 1 3 4 7 oppglemOLD R=O
9 2 8 eqtri ˙=O