Metamath Proof Explorer


Theorem oppgle

Description: less-than relation of an opposite group. (Contributed by Thierry Arnoux, 13-Apr-2018)

Ref Expression
Hypotheses oppglt.1 O = opp 𝑔 R
oppgle.2 ˙ = R
Assertion oppgle ˙ = O

Proof

Step Hyp Ref Expression
1 oppglt.1 O = opp 𝑔 R
2 oppgle.2 ˙ = R
3 df-ple le = Slot 10
4 10nn 10
5 2re 2
6 2lt10 2 < 10
7 5 6 gtneii 10 2
8 1 3 4 7 oppglem R = O
9 2 8 eqtri ˙ = O