Metamath Proof Explorer


Theorem oppgval

Description: Value of the opposite group. (Contributed by Stefan O'Rear, 25-Aug-2015) (Revised by Mario Carneiro, 16-Sep-2015) (Revised by Fan Zheng, 26-Jun-2016)

Ref Expression
Hypotheses oppgval.2 ⊢ + ˙ = + R
oppgval.3 ⊢ O = opp 𝑔 ⁡ R
Assertion oppgval ⊢ O = R sSet + ndx tpos + ˙

Proof

Step Hyp Ref Expression
1 oppgval.2 ⊢ + ˙ = + R
2 oppgval.3 ⊢ O = opp 𝑔 ⁡ R
3 id ⊢ x = R → x = R
4 fveq2 ⊢ x = R → + x = + R
5 4 1 eqtr4di ⊢ x = R → + x = + ˙
6 5 tposeqd ⊢ x = R → tpos + x = tpos + ˙
7 6 opeq2d ⊢ x = R → + ndx tpos + x = + ndx tpos + ˙
8 3 7 oveq12d ⊢ x = R → x sSet + ndx tpos + x = R sSet + ndx tpos + ˙
9 df-oppg ⊢ opp 𝑔 = x ∈ V ⟼ x sSet + ndx tpos + x
10 ovex ⊢ R sSet + ndx tpos + ˙ ∈ V
11 8 9 10 fvmpt ⊢ R ∈ V → opp 𝑔 ⁡ R = R sSet + ndx tpos + ˙
12 fvprc ⊢ ¬ R ∈ V → opp 𝑔 ⁡ R = ∅
13 reldmsets ⊢ Rel ⁡ dom ⁡ sSet
14 13 ovprc1 ⊢ ¬ R ∈ V → R sSet + ndx tpos + ˙ = ∅
15 12 14 eqtr4d ⊢ ¬ R ∈ V → opp 𝑔 ⁡ R = R sSet + ndx tpos + ˙
16 11 15 pm2.61i ⊢ opp 𝑔 ⁡ R = R sSet + ndx tpos + ˙
17 2 16 eqtri ⊢ O = R sSet + ndx tpos + ˙