Metamath Proof Explorer


Theorem ply1sclcl

Description: The value of the algebra scalar lifting function for (univariate) polynomials applied to a scalar results in a constant polynomial. (Contributed by AV, 27-Nov-2019)

Ref Expression
Hypotheses ply1scl.p ⊢ P = Poly 1 ⁡ R
ply1scl.a ⊢ A = algSc ⁡ P
coe1scl.k ⊢ K = Base R
ply1sclf.b ⊢ B = Base P
Assertion ply1sclcl ⊢ R ∈ Ring ∧ S ∈ K → A ⁡ S ∈ B

Proof

Step Hyp Ref Expression
1 ply1scl.p ⊢ P = Poly 1 ⁡ R
2 ply1scl.a ⊢ A = algSc ⁡ P
3 coe1scl.k ⊢ K = Base R
4 ply1sclf.b ⊢ B = Base P
5 1 2 3 4 ply1sclf ⊢ R ∈ Ring → A : K ⟶ B
6 5 ffvelcdmda ⊢ R ∈ Ring ∧ S ∈ K → A ⁡ S ∈ B