Metamath Proof Explorer


Theorem pm13.195

Description: Theorem *13.195 in WhiteheadRussell p. 179. This theorem is very similar to sbc5 . (Contributed by Andrew Salmon, 3-Jun-2011) (Revised by NM, 4-Jan-2017)

Ref Expression
Assertion pm13.195 yy=Aφ[˙A/y]˙φ

Proof

Step Hyp Ref Expression
1 sbc5 [˙A/y]˙φyy=Aφ
2 1 bicomi yy=Aφ[˙A/y]˙φ