Metamath Proof Explorer


Theorem pm5.21nd

Description: Eliminate an antecedent implied by each side of a biconditional. Variant of pm5.21ndd . (Contributed by NM, 20-Nov-2005) (Proof shortened by Wolf Lammen, 4-Nov-2013)

Ref Expression
Hypotheses pm5.21nd.1 ⊢ φ ∧ ψ → θ
pm5.21nd.2 ⊢ φ ∧ χ → θ
pm5.21nd.3 ⊢ θ → ψ ↔ χ
Assertion pm5.21nd ⊢ φ → ψ ↔ χ

Proof

Step Hyp Ref Expression
1 pm5.21nd.1 ⊢ φ ∧ ψ → θ
2 pm5.21nd.2 ⊢ φ ∧ χ → θ
3 pm5.21nd.3 ⊢ θ → ψ ↔ χ
4 1 ex ⊢ φ → ψ → θ
5 2 ex ⊢ φ → χ → θ
6 3 a1i ⊢ φ → θ → ψ ↔ χ
7 4 5 6 pm5.21ndd ⊢ φ → ψ ↔ χ