Description: Eliminate an antecedent implied by each side of a biconditional. Variant of pm5.21ndd . (Contributed by NM, 20-Nov-2005) (Proof shortened by Wolf Lammen, 4-Nov-2013)
Ref | Expression | ||
---|---|---|---|
Hypotheses | pm5.21nd.1 | |
|
pm5.21nd.2 | |
||
pm5.21nd.3 | |
||
Assertion | pm5.21nd | |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | pm5.21nd.1 | |
|
2 | pm5.21nd.2 | |
|
3 | pm5.21nd.3 | |
|
4 | 1 | ex | |
5 | 2 | ex | |
6 | 3 | a1i | |
7 | 4 5 6 | pm5.21ndd | |